Sandbox Reserved 714: Difference between revisions
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The reaction proceeds in two steps, including the formation of a covalent intermediate. | The reaction proceeds in two steps, including the formation of a covalent intermediate. | ||
First, the substrate (epoxide) is accepted in the active site and its oxygen forms hydrogen bonds with Y383 and Y466. The oxygen of D335 attacks one of the two carbons included in the epoxide function. As a result, the oxygen of the subtrate takes the hydrogen of the hydroxyl function of Y466: the covalent intermediate is formed, and linked to D335. | First, the substrate (epoxide) is accepted in the active site and its oxygen forms hydrogen bonds with Y383 and Y466. The oxygen of D335 attacks one of the two carbons included in the epoxide function. As a result, the oxygen of the subtrate takes the hydrogen of the hydroxyl function of Y466: the covalent intermediate is formed, and linked to D335. | ||
Then, the oxygen negatively charged belonging to the lateral chain of Y383 attacks the hydrogen of H524. After that, a water molecule enters the active site. The hydroxyl of D335 is therefore renewed, the diol product is created and released. The active site is available for a new catalytic cycle. | |||
The corresponding reaction equation is the following: | |||
Epoxide + H<sub>2</sub>O ↔ Glycol | |||
=== N-terminal domain === | === N-terminal domain === | ||
Revision as of 15:35, 2 January 2013

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DUTREUX Fabien, BONHOURE Anna
