Sandbox Reserved 969: Difference between revisions

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Moreover we may underscore a higher affinity for K+ than Na+ because of several reason :

First, we can find 4 ~~backbone~~ carbonyl oxygen from <scene name='60/604488/Val64/1'>Val64</scene> which participate in K+ and Rb+ ions chelation because of the formation of an octahedral ligand: an octahedral arrangement oxygen ligands in the channel pore is more favorable for K+ than Na+.

First, we can find 4 backbones carbonyl oxygen from <scene name='60/604488/Val64/1'>Val64</scene> which participate in K+ and Rb+ ions chelation because of the formation of an octahedral ligand: an octahedral arrangement oxygen ligands in the channel pore is more favorable for K+ than Na+.

The lack of selectivity is due to the fact that the NaK channel have an almost identical structure when it is in complex with Na+, K+ or Rb+ : there is no big rearrangement in the structure of the protein depending on the bound ion. So the structure is stable with any ions, so it is non selective. Moreover, it could have a heavy atom contamination but it happens in a smaller extent with K+ than with Na+.

Sandbox Reserved 969: Difference between revisions

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@@ Line 75: / Line 75: @@
 Moreover we may underscore a higher affinity for K+ than Na+ because of several reason :
-First, we can find 4 backbone carbonyl oxygen from <scene name='60/604488/Val64/1'>Val64</scene> which participate in K+ and Rb+ ions chelation because of the formation of an octahedral ligand: an octahedral arrangement oxygen ligands in the channel pore is more favorable for K+ than Na+.
+First, we can find 4 backbones carbonyl oxygen from <scene name='60/604488/Val64/1'>Val64</scene> which participate in K+ and Rb+ ions chelation because of the formation of an octahedral ligand: an octahedral arrangement oxygen ligands in the channel pore is more favorable for K+ than Na+.
 The lack of selectivity is due to the fact that the NaK channel have an almost identical structure when it is in complex with Na+, K+ or Rb+ : there is no big rearrangement in the structure of the protein depending on the bound ion. So the structure is stable with any ions, so it is non selective. Moreover, it could have a heavy atom contamination but it happens in a smaller extent with K+ than with Na+.