User:Sean Callahan/Sandbox 1: Difference between revisions
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==Mechanism== | ==Mechanism== | ||
The demethylation of lysine via LSD1 occurs through oxidation via a hydride transfer. Shown in Figure 2 the first step involves the <scene name='81/811710/Fad_highlight/1'>Flavin Adenine Dinucleotide cofactor</scene> initiating a hydride transfer from the one of the two methyl groups bound to the nitrogen at the lysine tail, via a N5 on the flavin group. An imine cation is then formed at the end of the lysine tail to compensate for the loss of hydride. The FAD co-factor is also negatively charged and lysine residue 661 provides stability by drawing that charge away. In the next step the imine is hydrolyzed and transitions to an hemiaminal. This then breaks down to formaldehyde and the product lysine. | The demethylation of lysine via LSD1 occurs through oxidation via a hydride transfer. Shown in Figure 2 the first step involves the <scene name='81/811710/Fad_highlight/1'>Flavin Adenine Dinucleotide cofactor</scene> initiating a hydride transfer from the one of the two methyl groups bound to the nitrogen at the lysine tail, via a N5 on the flavin group. [[Image:LSD1Mech2.jpg|400px|right|thumb|Figure 2]] An imine cation is then formed at the end of the lysine tail to compensate for the loss of hydride. The FAD co-factor is also negatively charged and lysine residue 661 provides stability by drawing that charge away. In the next step the imine is hydrolyzed and transitions to an hemiaminal. This then breaks down to formaldehyde and the product lysine. | ||
==Hydrophobic Pocket== | ==Hydrophobic Pocket== | ||
